<?xml version='1.0' encoding='UTF-8'?><?xml-stylesheet href="http://www.blogger.com/styles/atom.css" type="text/css"?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:georss='http://www.georss.org/georss' xmlns:gd='http://schemas.google.com/g/2005' xmlns:thr='http://purl.org/syndication/thread/1.0'><id>tag:blogger.com,1999:blog-8690669</id><updated>2011-04-21T12:05:30.779-07:00</updated><title type='text'>Mindy's Blog</title><subtitle type='html'></subtitle><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://period5mw.blogspot.com/feeds/posts/default'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8690669/posts/default?max-results=100'/><link rel='alternate' type='text/html' href='http://period5mw.blogspot.com/'/><link rel='hub' href='http://pubsubhubbub.appspot.com/'/><author><name>period5mw</name><uri>http://www.blogger.com/profile/08532237810678086711</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>9</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>100</openSearch:itemsPerPage><entry><id>tag:blogger.com,1999:blog-8690669.post-111652037338572944</id><published>2005-05-19T09:32:00.000-07:00</published><updated>2005-05-19T09:32:53.416-07:00</updated><title type='text'>Probability - 7</title><content type='html'>&lt;div style="float: right; margin-left: 10px; margin-bottom: 10px;"&gt; &lt;a href="http://www.flickr.com/photos/futureofmath/14473313/" title="photo sharing"&gt;&lt;img src="http://photos14.flickr.com/14473313_a13054433f_m.jpg" alt="" style="border: solid 2px #000000;" /&gt;&lt;/a&gt; &lt;br /&gt; &lt;span style="font-size: 0.9em; margin-top: 0px;"&gt;  &lt;a href="http://www.flickr.com/photos/futureofmath/14473313/"&gt;Probability - 7&lt;/a&gt;  &lt;br /&gt;  Originally uploaded by &lt;a href="http://www.flickr.com/people/futureofmath/"&gt;Misterteacher&lt;/a&gt;. &lt;/span&gt;&lt;/div&gt;The game we played was rock, paper, scissors.  What we did first before the game, was we set up a tree diagram to find the theoretical probability.The theoretical probabilities was 3/27(A), 18/27(B), and 6/27(C). Second, each of us made a prediction. Our prediction was that B would win. Our prediction was right and our theoretical probability was the same as our experimental probability. I think that this game is not fair cause B would win all the time then C then A&lt;br clear="all" /&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8690669-111652037338572944?l=period5mw.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://period5mw.blogspot.com/feeds/111652037338572944/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=8690669&amp;postID=111652037338572944' title='3 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/8690669/posts/default/111652037338572944'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8690669/posts/default/111652037338572944'/><link rel='alternate' type='text/html' href='http://period5mw.blogspot.com/2005/05/probability-7.html' title='Probability - 7'/><author><name>period5mw</name><uri>http://www.blogger.com/profile/08532237810678086711</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>3</thr:total></entry><entry><id>tag:blogger.com,1999:blog-8690669.post-111591565759687239</id><published>2005-05-12T09:34:00.000-07:00</published><updated>2005-05-12T09:34:17.630-07:00</updated><title type='text'>experimenta probability for stick or switch</title><content type='html'>&lt;div style="float: right; margin-left: 10px; margin-bottom: 10px;"&gt; &lt;a href="http://www.flickr.com/photos/futureofmath/13543983/" title="photo sharing"&gt;&lt;img src="http://photos9.flickr.com/13543983_cb1d06d44d_m.jpg" alt="" style="border: solid 2px #000000;" /&gt;&lt;/a&gt; &lt;br /&gt; &lt;span style="font-size: 0.9em; margin-top: 0px;"&gt;  &lt;a href="http://www.flickr.com/photos/futureofmath/13543983/"&gt;letsmakeadeal&lt;/a&gt;  &lt;br /&gt;  Originally uploaded by &lt;a href="http://www.flickr.com/people/futureofmath/"&gt;Misterteacher&lt;/a&gt;. &lt;/span&gt;&lt;/div&gt;&lt;br clear="all" /&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8690669-111591565759687239?l=period5mw.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://period5mw.blogspot.com/feeds/111591565759687239/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=8690669&amp;postID=111591565759687239' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/8690669/posts/default/111591565759687239'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8690669/posts/default/111591565759687239'/><link rel='alternate' type='text/html' href='http://period5mw.blogspot.com/2005/05/experimenta-probability-for-stick-or.html' title='experimenta probability for stick or switch'/><author><name>period5mw</name><uri>http://www.blogger.com/profile/08532237810678086711</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-8690669.post-111090806478098176</id><published>2005-03-15T09:17:00.000-08:00</published><updated>2005-03-16T09:10:58.006-08:00</updated><title type='text'>Composite Shapes Extended Response</title><content type='html'>I think the area of her yard is 5,750 and she would need the large bag. First, I made the sketch of her yard into smaller shapes. Second, I found the area of each shape. For the parollelogram i did base times height,for the square i did the same formula, and for the triangle i did base times height divided by 2. Third, I added the area of each shape together and for my answer I got 5,750. So, then she would need the large bag to fertilize her yard.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8690669-111090806478098176?l=period5mw.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://period5mw.blogspot.com/feeds/111090806478098176/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=8690669&amp;postID=111090806478098176' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/8690669/posts/default/111090806478098176'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8690669/posts/default/111090806478098176'/><link rel='alternate' type='text/html' href='http://period5mw.blogspot.com/2005/03/composite-shapes-extended-response.html' title='Composite Shapes Extended Response'/><author><name>period5mw</name><uri>http://www.blogger.com/profile/08532237810678086711</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-8690669.post-110874808176399796</id><published>2005-02-18T09:17:00.000-08:00</published><updated>2005-02-18T09:34:41.766-08:00</updated><title type='text'>Similar Triangles Extended Response</title><content type='html'>The way i got the answer to this problem is first i wrote a proportion.My proportion was 5ft over 25ft then 14ft over x. Second, i multiplied 25 by 14 and it came out to be 350. Third, I divided 350 by 5ft and and it gave me my answer. My answer of x came out to be 70.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8690669-110874808176399796?l=period5mw.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://period5mw.blogspot.com/feeds/110874808176399796/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=8690669&amp;postID=110874808176399796' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/8690669/posts/default/110874808176399796'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8690669/posts/default/110874808176399796'/><link rel='alternate' type='text/html' href='http://period5mw.blogspot.com/2005/02/similar-triangles-extended-response.html' title='Similar Triangles Extended Response'/><author><name>period5mw</name><uri>http://www.blogger.com/profile/08532237810678086711</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-8690669.post-110676072737879273</id><published>2005-01-26T09:11:00.001-08:00</published><updated>2005-01-26T09:32:07.380-08:00</updated><title type='text'>Sufficient Properties </title><content type='html'>  A square is a parallelogram because the property of a parallelogram is it has exactly two pairs of parallel lines. A square is also a rectangle because the oppisite sides are parallel, and it has 4 right angles. The way a square is a rhombus is because a rhombus is the oppisite sides are parallel, and all sides are congruent.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8690669-110676072737879273?l=period5mw.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://period5mw.blogspot.com/feeds/110676072737879273/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=8690669&amp;postID=110676072737879273' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/8690669/posts/default/110676072737879273'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8690669/posts/default/110676072737879273'/><link rel='alternate' type='text/html' href='http://period5mw.blogspot.com/2005/01/sufficient-properties_26.html' title='Sufficient Properties '/><author><name>period5mw</name><uri>http://www.blogger.com/profile/08532237810678086711</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-8690669.post-110676067517344525</id><published>2005-01-26T09:11:00.000-08:00</published><updated>2005-01-26T09:31:15.173-08:00</updated><title type='text'>Sufficient Properties </title><content type='html'>  A square is a parallelogram because the property of a parallelogram is it has exactly two pairs of parallel lines. A square is also a rectangle because the oppisite sides are parallel, and it has 4 right angles. The way a square is a rhombus is because a rhombus is the oppisite sides are parallel, and all sides are congruent.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8690669-110676067517344525?l=period5mw.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://period5mw.blogspot.com/feeds/110676067517344525/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=8690669&amp;postID=110676067517344525' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/8690669/posts/default/110676067517344525'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8690669/posts/default/110676067517344525'/><link rel='alternate' type='text/html' href='http://period5mw.blogspot.com/2005/01/sufficient-properties.html' title='Sufficient Properties '/><author><name>period5mw</name><uri>http://www.blogger.com/profile/08532237810678086711</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-8690669.post-110537756611922070</id><published>2005-01-10T08:29:00.000-08:00</published><updated>2005-01-10T09:19:26.120-08:00</updated><title type='text'>Derived Measurments Extended Reponse</title><content type='html'>   Marks heart beats 16 times in 15 seconds. At that rate, how many times will it beat in one minute? Be sure to include the appropiate unit.&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;Marks heart beat would be 64 beats/minute because if you start with 16 beats per 15 minutes you will have to multiply 16 and 15 by 2,3, and 4. Like this: 15 by 2, 15 by 3, 15 by 4 which equals 60 and that equals to 1 minute. You would do 16 the same way 16 by 2, 16 by 3, 16 by 4 which equals to 64. So if his heart beat keeps beating 16 beats per 15 minutes the answer would be 64 beats in one minute.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8690669-110537756611922070?l=period5mw.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://period5mw.blogspot.com/feeds/110537756611922070/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=8690669&amp;postID=110537756611922070' title='4 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/8690669/posts/default/110537756611922070'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8690669/posts/default/110537756611922070'/><link rel='alternate' type='text/html' href='http://period5mw.blogspot.com/2005/01/derived-measurments-extended-reponse.html' title='Derived Measurments Extended Reponse'/><author><name>period5mw</name><uri>http://www.blogger.com/profile/08532237810678086711</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>4</thr:total></entry><entry><id>tag:blogger.com,1999:blog-8690669.post-110209486553698662</id><published>2004-12-03T09:27:00.000-08:00</published><updated>2004-12-03T09:27:45.536-08:00</updated><title type='text'>Rational or Irrational?</title><content type='html'>&lt;div style="float: right; margin-left: 10px; margin-bottom: 10px;"&gt; &lt;a href="http://www.flickr.com/photos/10358224@N00/1830943/" title="photo sharing"&gt;&lt;img src="http://photos2.flickr.com/1830943_25da1caac6_m.jpg" alt="" style="border: solid 2px #000000;" /&gt;&lt;/a&gt; &lt;br /&gt; &lt;span style="font-size: 0.9em; margin-top: 0px;"&gt;  &lt;a href="http://www.flickr.com/photos/10358224@N00/1830943/"&gt;Rational or Irrational?&lt;/a&gt;  &lt;br /&gt;  Originally uploaded by &lt;a href="http://www.flickr.com/people/10358224@N00/"&gt;Misterteacher&lt;/a&gt;. &lt;/span&gt;&lt;/div&gt;This fraction 2/6 would be a rational number because you cant write irrational numbers as a fraction. The correct decimal would be a non terminating and repeating decimal.That type of decimal means it never ends and that it repeats.There for the fraction is a repeating and non terminating decimal.&lt;br clear="all" /&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8690669-110209486553698662?l=period5mw.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://period5mw.blogspot.com/feeds/110209486553698662/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=8690669&amp;postID=110209486553698662' title='1 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/8690669/posts/default/110209486553698662'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8690669/posts/default/110209486553698662'/><link rel='alternate' type='text/html' href='http://period5mw.blogspot.com/2004/12/rational-or-irrational.html' title='Rational or Irrational?'/><author><name>period5mw</name><uri>http://www.blogger.com/profile/08532237810678086711</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-8690669.post-109759844782463187</id><published>2004-10-12T09:15:00.000-07:00</published><updated>2004-10-14T09:26:28.603-07:00</updated><title type='text'>introduction</title><content type='html'>Dear mom and dad,&lt;br /&gt;&lt;br /&gt;  I am going to tell you guys about mean, medium, and mode.They are easy to do right after someone tells you how to do it.Which i'm going to explain it to you now.So just listen.&lt;br /&gt;  First, i'll tell you about mean and how good i do at it.All you do is simply add all the numbers there. For example say you got these scores in a test, 95,56,85,70,60. You would add them up and divide them by 5 because thats how many number of scores you got. Mean helped me in math by teaching me the average.&lt;br /&gt;   Second, is medium and medium is way easier than mean.In medium you put all the numbers in order.Lets use the same numbers.56,60,70,85,95.You just look at the very middle number.So it would be 70.Thats it.This helped me in math by teaching me how to do the medium.&lt;br /&gt;   Third,is mode. Mode is easy too. All you got to do is see which number accures the most. The same scores that you got dont have a mode.So lets say these are your new scores:97,97 86,75,100,98,and 100. The mode here would be both 97, and 100.This helped me by showing me to do mode.&lt;br /&gt;&lt;br /&gt;love&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8690669-109759844782463187?l=period5mw.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://period5mw.blogspot.com/feeds/109759844782463187/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=8690669&amp;postID=109759844782463187' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/8690669/posts/default/109759844782463187'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8690669/posts/default/109759844782463187'/><link rel='alternate' type='text/html' href='http://period5mw.blogspot.com/2004/10/introduction.html' title='introduction'/><author><name>period5mw</name><uri>http://www.blogger.com/profile/08532237810678086711</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry></feed>
